A motor boat is observed to travel 10km/h relative to the earth in the direction 37° north of east. if the velocity of the boat sure that the wind only is 2km/h westward and that due to the current only is 4km/h southward, what is the magnitude of direction of the velocity of the boat due to its own power
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Answered by
55
East - i vector North - j vector.
Boat velocity = Own velocity + Wind velocity + Current velocity.
Written as:
Vb = Vit + Vw + Vr
10(cos 37 i + sin 37 j) = Vit + (-2 i) + (-4 j)
8 i + 6 j = Vit + (-2 i) + (-4 j)
Vit = 10 i + 10 j
The boat travels at 14.14 km/ph 45 degrees north of east because of its own power.
Answered by
4
Answer: 14.14 kmph, 45 degrees north of east
Explanation:
East - i vector North - j vector.
Vel of boat = vel of itself + vel of wind + vel of current.
Vb = Vit + Vw + Vr
10(cos 37 i + sin 37 j) = Vit + (-2 i) + (-4 j)
8 i + 6 j = Vit + (-2 i) + (-4 j)
Vit = 10 i + 10 j
Boat travels at 14.14 kmph 45deg north of east
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