Question

A motor boat move at a steady speed of 4m/s. Water resistance acting on it is 4000 N . Calculate the power of its engine

Answer 1

Answer: Power is the rate of doing work.

Power of Engine = Fv

=4000*4

=16000w

=16kw

Explanation:

Answer 2

The power of the engine is $16\times10^3W$

Explanation:

As we know that the power is define as the rate of doing work.

It is written as,

$P=\frac{dW}{dt}$

Here, W = Fx ( F= force and x = distance)

$P=\frac{Fdx}{dt}$

$P=Fv$    ($\frac{dx}{dt}=v$)

Given F = 4000 N  and v = 4 m/s.

Substitute these values in above formula, we get

$P=4000N\times4m/s$

$P=16\times10^3W$

Thus, the power of the engine is $16\times10^3W$

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Topic: Power

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