A motor boat moves at a steady speed of 4ms-1. water resistance acting on it is 4000N. Calculate the power of its engine.
Answers
Answer:
The power of the engine is 16\times10^3W16×10
3
W
Explanation:
As we know that the power is define as the rate of doing work.
It is written as,
P=\frac{dW}{dt}P=
dt
dW
Here, W = Fx ( F= force and x = distance)
P=\frac{Fdx}{dt}P=
dt
Fdx
P=FvP=Fv (\frac{dx}{dt}=v
dt
dx
=v )
Given F = 4000 N and v = 4 m/s.
Substitute these values in above formula, we get
P=4000N\times4m/sP=4000N×4m/s
P=16\times10^3WP=16×10
3
W
Thus, the power of the engine is 16\times10^3W16×10
3
W
PLZ UNDERSTAND ABOVE MATTER SORRY
I HOPE IT IS HELPFUL
PLZ FOLLOW ME AND MRAKE ME AS BRAINLIEST ANSWER
Answer:
Speed Of The Boat = 4ms-1
Resistance Force Acting On It = 4000N
Power = ?
P = F x V
P = 4000 x 4
P = 16000W
P = 16kW
Explanation:
>.< Simple Answer LOL @o@