Question

A motor boat moves at a steady speed of 4ms-1. water resistance acting on it is 4000N. Calculate the power of its engine.​

Answer 1

Answer:

The power of the engine is 16\times10^3W16×10

3

W

Explanation:

As we know that the power is define as the rate of doing work.

It is written as,

P=\frac{dW}{dt}P=

dt

dW

Here, W = Fx ( F= force and x = distance)

P=\frac{Fdx}{dt}P=

dt

Fdx

P=FvP=Fv (\frac{dx}{dt}=v

dt

dx

=v )

Given F = 4000 N and v = 4 m/s.

Substitute these values in above formula, we get

P=4000N\times4m/sP=4000N×4m/s

P=16\times10^3WP=16×10

3

W

Thus, the power of the engine is 16\times10^3W16×10

3

W

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Answer 2

Answer:

Speed Of The Boat = 4ms-1

Resistance Force Acting On It = 4000N

Power = ?

                   P = F x V

                   P = 4000 x 4

                   P = 16000W

                   P = 16kW

Explanation:

                         >.< Simple Answer   LOL @o@