A motor boat moves at a steady speed of 8 m/s . If the water resistance to the motion of the boat is 2kN. Calculate the power of the engine?
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Dear student;
AS U KNOW THAT 2KN =2000N
power is the rate of doing work =dw/dt
= dFx/dt (work = Fx)
= Fv
power of engine = 2000*8
= 16000w
= 16kw
AS U KNOW THAT 2KN =2000N
power is the rate of doing work =dw/dt
= dFx/dt (work = Fx)
= Fv
power of engine = 2000*8
= 16000w
= 16kw
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