Question

A motor boat starting from rest of a lake accelerates in a straight line at constant rate of 3m/sec square for 8 second.How far does the boat travel during this time?

Answer 1

нєℓℓσ мαтє

нєяє ιѕ уσυя ѕσℓυтισи

Given : a = 3 m/s²
u = 0 m/s
t = 8 s

v = u + at
v = 0 + ( 3 ) ( 8 )
v = 24 m/s

v² - u² = 2as
24² - 0² = 2( 3 )( s )
24*24 / 6 = s
24*4 = s
96 m = s

нєи¢є ¢αя тяανєℓℓє∂ 96 м ∂υяιиg тнιѕ тιмє.

нσρє ιт нєℓρѕ

Answer 2

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.