Question

a motor boat starting from rest on a lake accarates in a straight line at a constant rate of 3m/s2 from 8s. how for does the boat travel during this time?

Answer 1

u = 0
a = 3m/s²
t = 8
s = ut + 1/2at²
s = 0*8 + 1/2(3*8²)
s = 0 + 1/2(3*64)
s = 1/2(192)
s = 96
so boat travels 96m in 8 sec

Answer 2

Answer:

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

• u is initial velocity
• t is time
• a is acceleration
• s is distance travelled

We have ,

u = 0 [starting from rest]

• t = 8 sec
• a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.