Question

a motor boat starting from rest on a lake accelerates a straight line at a constant rate of 3m/s for 8seconds. how far does the boat travels during that time
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Answer 1

Answer:

96m

Explanation:

s=ut+1/2at^2

u=0;a=3;t=5

s=1/2×3×(8)^2

1/2×3×64=32×3

=96m

Answer 2

✬ Distance covered = 96 m ✬

Explanation:

Given:

• A motor boat started from rest (u) = 0 m/s
• Acceleration produced by boat (a) = 3 m/s².
• Time (t) = 8 seconds.

To Find:

• How far does the boat travels during that time ?

Formula to be used:

• S = ut + 1/2at²

Solution: By using the second law of motion we can find the distance covered by the boat.

Put the values on formula:-

$\implies{\rm }$ s = ut + 1/2at²

$\implies{\rm }$ s = 0 $\times$ 10 + 1/2 $\times$ 3 $\times$ (8)²

$\implies{\rm }$ s = 0 + 3/2 $\times$ 64

$\implies{\rm }$ s = 3 $\times$ 32

$\implies{\rm }$ s = 96 m

Hence, the distance covered by the motor boat during that time is 96 m.

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★ Know the terms ★

➟ u = Initial Velocity

➟ v = Final Velocity

➟ t = Time taken

➟ s = Distance