Question

A motor boat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0m s for 8.0s . How far does the boat travel during this time

Answer 1

Answer:

Initial velocity= 3m/s (u)

Time taken = 8second (t)

As acceleration (a) is constant

final velocity = 3m/s (v)

Using formula's,

v= u + at

3 = 3+ a(8)

a= 0

Distance (s) = ut + [a(t^2)]/2

. = 3(8) + [(0)(64)]/2

. = 24m

Hope it helps

Answer 2

Explanation:

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.