Question

A motor boat starting from rest on a lake accelerates in a straight line at a constant rate of 5.0m/s square for 15.0s how far does the boat travel during this time

Answer 1

Answer:

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

• u = 0 [starting from rest]
• t = 8 sec
• a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.

Answer 2

Answer:

Given, initial velocity of the boat = 0 m/s

Acceleration of the boat = 3 ms-2

Time period = 8s

As per the second motion equation, s = ut + 1/2 at2

Therefore, the total distance traveled by boat in 8 seconds = 0 + 1/2 (3)(8)2

= 96 meters

Therefore, the motorboat travels a distance of 96 meters in a time frame of 8 seconds.

Explanation:

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