Question

A motor boat starting from rest on a lake accelerates in a straight line at a constant rate of 4ms-2 for 10sec. How far does the boat travel during this time

Answer 1

We have ,
u = 0 m/s
a = 4 ms^-2
t= 10 s

From the second equation of motion
$s = ut \: + 1 \div 2 \times at {}^{2}$
= 0 + 1/2 × 4 × 10 × 10
=200 m

Answer 2

Answer:

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

• u = 0 [starting from rest]
• t = 8 sec
• a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.