Question

a motor boat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 m s-2 for 8.0 s. how far does the boat travel during this time?

Answer 1

u=0 and a= 3 t=8 so
s=ut+1/2at^2
so by this
s=0×8 + 1/2×3×8×8
s=0+192/2
s=96m it is the answer
mark it as brain list answer

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

★Given :-

u = 0 (Initial velocity)

a = 3.0 m/s²

t = 8.0 s (Time)

★To find :-

s = ? (Distance Travelled)

★Solution :-

${\boxed{\sf\:{Using\; second\; Equation\;of\;Motion}}}$

$\tt{\rightarrow s=ut+\dfrac{1}{2}at^{2}}$

$\tt{\rightarrow s=0\times 8.0+\dfrac{1}{2}\times 3.0\times (8.0)^{2}}$

$\tt{\rightarrow s=0+\dfrac{1}{2}\times 3.0\times (8.0)^{2}}$

$\tt{\rightarrow s=\dfrac{1}{2}\times 3.0\times 64}$

= 96 m

★Hence we get :-

${\boxed{\sf\:{Distance\;travelled\;by\;boat = 96 m}}}$

$\boxed{\begin{minipage}{11 cm} Additional Information \\ \\ \ Distance = Speed\times Time \\ \\ Displacement=Velocity\times time \\ \\ Average\; Speed = \dfrac{Initial\:\:Speed+Final\:\:Speed}{2} \end{minipage}}$