Question

A motor boat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 ms-2 for 8.0 S. How far does the boat travel during this time?

Answer 1

hey friend, here is your answer......

As the motor boat is starting from rest, so initial velocity (u)=0.
Givwn that, acceleration =3.0ms^-2
and time taken=8.0 sec.
We know that, s=ut+1/2at^2
so,the distance travelled by the boat during this time =(0×8)+ (1/2×3×8×8)m
=96 m.
So, the boat travelled 96m.
It may be your answer.....
Please mark as the brainliest if it helped you......

Answer 2

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.