Question

a motor boat starting from rest on a lake accelerates ina straight line at a constant rate of 3m/s^2 for 8 seconds. how far does the boat travel during this time??

Answer 1

GIVEN:

• Initial Velocity (u) = 0 m/s
• Acceleration (a) = 3 m/s²
• Time taken (t) = 8 seconds

TO FIND:

• Find the distance covered by the motor boat ?

SOLUTION:

Let the distance of the motor boat be 's' m

❖ We know that the formula for finding the distance covered by the motor boat is:-

$\large\bf{\star \: s = ut + \dfrac{1}{2} at^2 \: \star}$

According to question:-

$\rm{\dashrightarrow s = 0 \times 8 + \dfrac{1}{2} \times 3 \times (8)^2 }$

$\rm{\dashrightarrow s = 0 + \dfrac{1}{\cancel{2}} \times 3 \times \cancel{ 64} }$

$\rm{\dashrightarrow s = 3 \times 32}$

$\bf{\dashrightarrow s = 96 \: m}$

❛ Hence, the distance covered by the motor boat is 96 m ❜

______________________

✰ Extra Information ✰

↠First equation of motion = v = u + at

↠Third equation of motion = v² - u² = 2as

Answer 2

Given,

• Initial Velocity (u) = 0
• Acceleration (a) = 3m/s²
• Time (t) = 8 Second

To Find,

• The Distance Travelled by the Boat .

Solution,

$\implies$ We Know that :

$\bigstar \boxed{\boxed{\orange{\sf{s = ut + \dfrac{1}{2}at^{2}}}}}$

║Here,

• s = Distance
• u = Initial Velocity
• t = Time
• a = Acceleration ║

Now Put the Value in this Equation :

$\longrightarrow \sf{s = 0 \times 8 + \dfrac{1}{2} \times 3 \times (8)^{2}}$

$\longrightarrow \sf{s = \dfrac{1}{2} \times 3 \times 62}$

$\longrightarrow \sf{s = 3 \times 32}$

$\longrightarrow \boxed{\sf{s = 96m}}$

Therefore,

$\mapsto \boxed{\pink{\mathfrak{The\:Distance\:Covered\:by\:the\:Motar\:Boat - 96m}}}$

$\rule{200}2$