Question

A motor boat starting from rest
on a lake acceleration in a straight line at a constant rate of 3.0ms-2 for 8.0sec how far does the boat travel during this time?

Answer 1

Answer:

Initial velocity, u = 0m/s

Using the second equation of Motion,

$s = ut + \frac{1}{2} a {t}^{2}$

$= 0 \times 8 + \frac{1}{2} \times 3 \times 8 \times 8$

$= 0 + 96$

$= 96 \: metres$

So, the motorboat covered 96 metres.

☄Hope it helps uh☄

Answer 2

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.