Question

a motor boat starting from rest on a lake acceleration in a straight line at a constant rate of 3.0ms-2 for 8 second how far does the boat travel this time ​

Answer 1

$\:\sf\underline\red{Given\::-}\:$

• U = 0 $\dfrac{m}{s}^{-2}$

• A = 3 $\dfrac{m}{s}^{-2}$

• T = 8 seconds

$\:\sf\underline\purple{By\:using}\:$

$\boxed {S\:=ut\:+\: \dfrac{1}{2}{at}^{2}}$

$\hookrightarrow\:s\:=\:0\:×\:8\:+\: \dfrac{1}{2}\:×\:3\:×\:{8}^{2}$

$\hookrightarrow\:s\:=\:96m$

$\displaystyle\huge\blue{\underline{\underline{Points\:to\:remember}}}$

• Average speed = $\</strong><strong>d</strong><strong>frac{</strong><strong>Total\</strong><strong>:</strong><strong>Distance</strong><strong>}{</strong><strong>Time\</strong><strong>:</strong><strong>taken</strong><strong>}$

• V= u +at

• $</strong><strong>\</strong><strong>b</strong><strong>o</strong><strong>l</strong><strong>d</strong><strong>{</strong><strong>v</strong><strong>}^{2}$ = ${</strong><strong>u</strong><strong>}^{2}$ + 2as

• Average velocity = $\dfrac{Total\:Displacement}{Time\:taken}$

Answer 2

$\huge\rm\purple{Answer:}$

Given that:

Initial velocity of motorboat, u = 0

Acceleration of motorboat, a=3.0ms-2

Time under consideration, or time taken t = 8.0s

Formula:

We know the equation of motion

Distance, s=ut + (1/2)at2 —————-(i)

Substituting the given and known values in equation (i) we get,

s= o (8) + 1/2 (3) (8)2

= 1/2 (3) (64) { 82 = 8 X 8=64}

= 3 (32)

= 96

Therefore, The distance travel by motorboat = 96 m