Physics, asked by abdulmuttalib15, 1 year ago

A motor boat starting from rest on a lake in a straight line with a constant rate of 3ms-2 for 8 sec. How far boat travel during this time

Answers

Answered by adarshhoax
5
Hey friend

here is your answer

time ( t ) = 8 second
acceleration ( a ) = 3m/sec^-2
initial velocity ( u ) = 0m/sec

displacement ( s ) = ? ( to find )

as
s = ut +  \frac{1}{2} a {t}^{2}  \\ s = 0 \times 8 +  \frac{3}{2}  \times  {8}^{2}  \\ s = 0 + 96 \\ s = 96 \: metre
so, distance covered = 96 metres


glad to help you
hope it helps
thank you.
Answered by Anonymous
6

a = 3 ms^-2

t = 8 second

u = 0

s = ?

Using 2nd equation of Motion

{\implies s = ut + \dfrac{1}{2}at^{2}}

{\implies s = 0\times 8 + \dfrac{1}{2}\times 3\times (8^{2})}

{\implies s = 0 + \dfrac{1}{2}\times 3\times 64}

= 96  m

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