a motor boat starting from rest on the lake accelerates in the straight line at a constant rate of 3 M per second square for 8 second how does it travels at last
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1
given :-
u (initial velocity) = 0m/s
acceleration = 3m/s²
time = 8 seconds
we have to find the distance travelled by the motor boat in 8 seconds.
by using second equation of motion. that is s = ut + 1/2 at²
where s is the distance.
==> s = (0 × 8) + 1/2 × 3 × (8)²
==> s = 0 + 3/2 × 64
==> s = 3 × 32
==> s = 96m
hence, the motor boat travelled 96m in 8 seconds.
HOPE THIS HELPS..!!
u (initial velocity) = 0m/s
acceleration = 3m/s²
time = 8 seconds
we have to find the distance travelled by the motor boat in 8 seconds.
by using second equation of motion. that is s = ut + 1/2 at²
where s is the distance.
==> s = (0 × 8) + 1/2 × 3 × (8)²
==> s = 0 + 3/2 × 64
==> s = 3 × 32
==> s = 96m
hence, the motor boat travelled 96m in 8 seconds.
HOPE THIS HELPS..!!
Answered by
2
Here ,
Distance travelled , s = ?
Initial speed , u = 0
Time , t = 8.0 s
Acceleration , a = 3.0 m / s ²
Now ,
s = ut + 1/2 at²
s = 0 * 8.0 + 1/2 * 3 * ( 8.0 )²
s = 0 + 1/2 * 3 * 64
s = 96 m
Thus , the boat travels a distance of 96 metres.
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