Question

A motor boat starts from rest. After one minute it's Velocity becomes 72km/h.
Calculate-

1 Acceleration
2 Distance

Answer 1

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i.) The initial Velocity (U) = 0
The final Velocity (V) = 72km/h = 20m/s
Time (T) = 1 minute = 60 secs

Acceleration


$a \: = \frac{v - u}{t}$


$a \: = \frac{20 - 0}{60}$


$a \: = \frac{1}{3} \: m{s}^{2} \: \: \: \: \: \: \: \: \boxed{ans}$


ii.) Let's use the second equation of motion


$s = ut + \frac{1}{2} a {t}^{2} \: \: > {s\: \: is \: distance} <$


$s = 0 \times t + \frac{1}{2} \times \frac{1}{3} \times 60 \times 60$


$s = 0 + 10 \times 60$


$s = 600m \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ans}$

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Hope this helps. . . . . . ❤❤

Answer 2

Hi there!

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Given :

Initial velocity (u) = 0

Final velocity (v) = 72 km/h = 72 × 5/18

Final velocity (v) = 20 m/s.

Time taken (t) = 1 min = 60 secs.

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To find :

Acceleration (a) =?

Distance (s) =?

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Solution :

Question I :

Here, we will use first equation of motion,

v = u + at

⇒a = v - u / t

⇒a = 20 - 0 / 60

⇒ a = 20 / 60

⇒ a = 1 / 3 m/s²

Hence, the required acceleration is 1 / 3 m/s²

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Question II :

Here, we will use third equation of motion ;

S = ut + 1 /2 at²

S = 0 × 60 + 1 / 2 × 1 / 3 × 60 × 60

S = 1 / 6 × 3600

S = 600 m.

Hence, the required distance is 600 m.

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Thanks for the question!

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