Question

A motor boat starts from the rest on a lake and accelerate in a straight line. as constant rate of 3 m/s² for 8 sec. How far does the boat travel during this time

Answer 1

Answer :- 96 m

Step by Step Explanation :-

♦Given that

▪Initial Velocity ( u ) → 0 [ as it starts from rest.]

▪Time ( t ) → 8 seconds

▪Acceleration a = 3 m/s²

⚫To find :- distance travelled (s )

=> Using the second equation of motion

S = ut + ½at²

S = 0 × 8 + ½ × 3 × 64

S = 3 × 32

= 96 m

•°• Distance travelled is 96 m!

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Answer 2

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.