A motor boat whose speed in still water is 18 km/h, takes 1 hour more to go 24
km upstream than to return downstream to the same spot. Find the speed of
the stream
Answers
- Speed of moter boat in still water is 18 km/hr
- While going with upstream takes 1 hr more then going with downstream for the same 24 km
- The speed of stream
- Let the speed of stream be 's'
- Let the time taken in stream be 'T1'
- Let the time taken in downstream be 'T2'
➠ 18 - s
➠ 18 + s
We know that ,
⚊⚊⚊⚊ ⓵
For upstream
- Time = T1
- Distance = 24 km
- Speed = 18 - s
⟮ Putting the values in ⓵ ⟯
: : ➜
: ➜ ⚊⚊⚊⚊ ⓶
For downstream
- Time = T2
- Distance = 24 km
- Speed = 18 + s
⟮ Putting the values in ⓵ ⟯
: : ➜
: ➜ ⚊⚊⚊⚊ ⓷
Given that ,time taken in upstream is 1 hour more than time taken in downstream for 24 km
Thus,
: ➜ T1 = T2 + 1
From ⓶ & ⓷
: ➜
: ➜
: ➜
: ➜ (42 + s)(18 - s) = 24(18 + s)
: ➜ 756 - 42s + 18s - s² = 432 + 24s
: ➜ s² + 24s + 42s - 18s - 756 + 432 = 0
: ➜ s² + 48s - 324 = 0
: ➜ s² + 54s - 6s - 324 = 0
: ➜ s(s + 54) -6(s + 54) = 0
: ➜ (s + 54)(s - 6) = 0
- s = - 54
- s = 6
As speed can't be negative
Thus ,
: : ➨ s = 6 km/hr
- Hence the speed of stream is 6 km/hr
Let the speed of the stream be x km\hr.
The speed of the boat upstream = (18 - x) km/hr
The speed of the boat downstream = (18 + x) km/hr
Distance = 24 km
As given in the question,
Time for upstream = 1 + Time for downstream
24/(18 - x) = 1 + 24/(18 + x)
24/(18 - x) - 24/(18 + x) = 1
x2 + 48x - 324 = 0
(x + 54)(x - 6) = 0
x ≠ - 54 as speed cannot be negative.
x = 6
The speed of the stream = 6 km/hr