a motor boat whose speed is 18 km/h in still water takes one hour to go 24km up steam than to return down steam to the same spot Find the speed of the steam
Answers
Answer:
Given parameters:
The speed of the motorboat in still water =18 kmph
Let us consider
The speed of the stream = s
Speed of boat upstream = Speed of a boat in still water – the speed of a stream
Speed of boat upstream = 18 – s
Speed of boat downstream = Speed of a boat in still water + speed of a stream
Speed of boat downstream = 18 + s
Time is taken for upstream = Time taken to cover downstream + 1
time =distance/speed
DistanceupstreamSpeedupstream=DistancedownstreamSpeeddownstream+1
24/ (18 – s) = [24/(18 + s)] + 1
24(18+s) = 24(18−s) + (18−s)(18+s)
s2 + 48s − 324 = 0
s2 + 54s − 6s − 324 = 0
(s+54)(s−6) = 0
s = 6,−54 but
s ≠−54
Since the speed of steam cannot be negative.
∴ s = 6km/hr
Step-by-step explanation:
Speed of boat in still water = 18km/hr
Let speed of the stream = s
Speed of boat upstream = Speed of boat in still water - speed of stream = 18−s
Speed of boat down stream = Speed of boat in still water + speed of stream = 18+s
Time taken for upstream = Time taken to cover downstream + 1
⇒ Distance upstream/speed upstream= Distance downstream/speed downstream + 1
⇒ 24/18-s= 24/18+s +1
⇒24(18+s)=24(18−s)+(18−s)(18+s)
s^2+48s-324=0
s^2+54s-6s-324=0
⇒(s+54)(s−6)=0
⇒s=6,−54
⇒s=-54
Thus, s=6km/hr, Speed of steam cannot be negative.