A motor-boat, whose speed is 9 km/h in still water goes 12 km downstream and comes back in a total time of 3 hours. Find the speed of the stream.
Answers
Answer:
Step-by-step explanation:
Information given to us:
- Speed of motor-boat = 9km/h
- In still water its speed goes upto 12km downstream
- Total time taken is 3 hours
What we have to calculate:
- Speed of stream?
Let us assume:
- Speed of stream be y km/hr
Speed of motor-boat in downstream:
As we have assumed speed as y km/hr. So speed of motor-boat in downstream would be found out by adding the speed of boat in still water with assumed speed.
- → (9 + y) km/hr
Speed of motor-boat in upstream:
As we have assumed speed as y km/hr. So speed of motor-boat in upstream would be found out by subtracting the speed of boat in still water with assumed speed.
- → (9 - y) km/hr
Formula needed to be used:
- T = D /S
Where,
- T denotes time
- D denotes distance
- S denotes speed
Finding out time taken for going 12 km downstream:
Again given,
- Distance = 12 km
- Speed = (9+x) km/hr
Applying the given formula of time.
- → (12 / 9+y) hr _______(1)
Finding out time taken for coming back from downstream:
Again given,
- Distance = 12km
- Speed = (9-x) km/hr
Applying the given formula of time:
- → (12 / 9-y) hr _______(2)
Adding both the equations which would be equal to 3 hours:
- → (12/9+y) + (12/9-x) = 3
Talking L.CM.,
- → (108 + 108 - 12y + 12y) / (9+y)(9-y) = 3
Opening the brackets in denominator and solving
- (9+y) (9-y)
- 9 (9-y) + y (9-y)
- 81 - 9y + 9y - y²
- 81 - y²
Again solving the equation,
- → (108 + 108 - 12y + 12y) / (81 - y²) = 3
- → (216) / (81 - y²) = 3
On cross multiplying we get,
- → 3 (81 - y²) = 216
Dividing 216 with 3,
- (81 - y²) = 216/3
Now,
- (81 - y²) = 72
Reversing the sides,
- -y² = 72 - 81
- -y² = -9
Negative signs would be cancelled,
- y² = 9
Taking square,
- y = √9
We gets, at last
- y = 3
Conclusion:
- Speed of the stream. is 3 km/hr