Question

a motor car being driven due north at 10 m s-1 turns through an angle of 180. if the car's speed remains unchanged during this turn, what is the change in velocity of the car

Answer 1

ANSWER: 40

EXPLANATION:

given that the speed remains same

we can say that the magnitude of velocity is same

only change occurs in its direction

after a turn of 180 degrees v becomes opposite. to its initial velocity

so final velocity = - initial velocity = - 20

where minus sign represents opposite direction.

so change in velocity = final velocity - initial velocity

= -20 - 20 = -40 (ans) = 40 (numericallY)

PLEASE MARK IT AS BRAINLIEST

Answer 2

Answer:

ANSWER: 20 m/s is southerly direction

Explanation:

$\sqrt{(10-(-10)^{2}} = \sqrt{400} = 20 m/s$

  1st answer pls mark as brainliest