Physics, asked by abhidhuri20, 6 months ago

A motor car driver doubles its velocity when he is having a turn. The force exerted

outwardly will be

a. Double

b. Half

c. 4 times

d. Times​

Answers

Answered by swathi21025
1

Answer:

c is the crt ans.........

Answered by saisahanan161010677
1

Answer:

Outward force      F=rmv2          

Outward force      F=rmv2          Now the velocity is doubled  i.e v′=2v

Outward force      F=rmv2          Now the velocity is doubled  i.e v′=2vNew outward force    F′=rm(2v)2=4F

Outward force      F=rmv2          Now the velocity is doubled  i.e v′=2vNew outward force    F′=rm(2v)2=4FThus the outward force becomes four times.

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