Question

A motor car had a wheel base of 2.743 m and pivot centres 1. 065m apart. the front and rear wheel track is 1.217 m .Calculate the correct angle of outside lock and
and turning circle radius of the outerrfront and inner rear wheels when the angle of inside lock is
40 degree.​

Answer 1

Explanation:

don't know but I can follow you if you mark me as brainliest

Answer 2

Answer:

c= 1.217m. b = 2.743 m. d = 1.065 m. ∆ = 40deg

sin€ = c- d/2r = 1.2-1/2r =