A motor car is going due north at a speed of 50km/h. It makes a 90° turn without changing the speed.
The change in velocity of the car is about ______?
a) 50km/h towards west.
b) 70km/h towards south-west.
c) 70km/h towards north-west.
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➖➖hello buddy here's ur answer......
⏩since the motor car is moving without changing speed , then it changes only the direction,, hence the magnitude remains same, but changes direction, i.e, along west,,, hence, the direction is along west ,,,
⏩so ans is 70km/h along south west,, because
⏩let the V1 be VELOCITY along j^ i.e, along y axis
⏹let the V2 be velocity along i^ i.e, along x axis.
then for finding the magnitude of change of VELOCITY,,
⏩∆V= √-V1^2-V2^2
⏩∆V= √(-50)^2+(-50)^2
⏩∆V= √2500+2500
⏩∆V= √5000
⏩∆V= 70.7km/h~70km/h
along south west
therefore option b is correct..
⏹⏹hope it helps you⏺⏺
⏩since the motor car is moving without changing speed , then it changes only the direction,, hence the magnitude remains same, but changes direction, i.e, along west,,, hence, the direction is along west ,,,
⏩so ans is 70km/h along south west,, because
⏩let the V1 be VELOCITY along j^ i.e, along y axis
⏹let the V2 be velocity along i^ i.e, along x axis.
then for finding the magnitude of change of VELOCITY,,
⏩∆V= √-V1^2-V2^2
⏩∆V= √(-50)^2+(-50)^2
⏩∆V= √2500+2500
⏩∆V= √5000
⏩∆V= 70.7km/h~70km/h
along south west
therefore option b is correct..
⏹⏹hope it helps you⏺⏺
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