Question

A motor car is going due north at a speed of 50km/h. It makes a 90° turn without changing the speed.

The change in velocity of the car is about ______?

a) 50km/h towards west.

b) 70km/h towards south-west.

c) 70km/h towards north-west.

Answer 1

➖➖hello buddy here's ur answer......

⏩since the motor car is moving without changing speed , then it changes only the direction,, hence the magnitude remains same, but changes direction, i.e, along west,,, hence, the direction is along west ,,,


⏩so ans is 70km/h along south west,, because


⏩let the V1 be VELOCITY along j^ i.e, along y axis

⏹let the V2 be velocity along i^ i.e, along x axis.

then for finding the magnitude of change of VELOCITY,,

⏩∆V= √-V1^2-V2^2

⏩∆V= √(-50)^2+(-50)^2

⏩∆V= √2500+2500

⏩∆V= √5000

⏩∆V= 70.7km/h~70km/h

along south west

therefore option b is correct..

⏹⏹hope it helps you⏺⏺

Answer 2

Answer:

Fb pe hoon bs as.. TA N YA.. same dp.. Comment box me msg jaa nhi paate ha