a motor car is moving with a velocity of 108 kilometre per hour and it takes 4 second to stop after the break are applied. calculate the force exerted by the breaks in Motor car is if its mass along with the passenger is 1000 kg
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u = 108 km/h
u = 108 × 5/18 m/s.
- u = 30 m/s.
- t = 4 seconds.
- v = 0 m/s
- m = 1000 Kg.
As we need to find Force applied for that we need to find acceleration of the motor car.
From first kinematics equation.
Substituting the values.
Now,applying Newton's second law.
Substituting the values.
Taking only magnitude gives.
☆ F = 7500N.
So,the Force applied by the brakes is 7500N .
The negative sign indicates that it is opposing the motion of the body.
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