Question

a motor car is moving with a velocity of 108 km/h and it takes 4s to stop after the brakes are applied. find the distance or covers before it comes to rest.​

Answer 1

Answer:

u = 108 km/h => 108×5/18 => 6×5 => 30 m/s

v = 0m/s

t = 4sec

therefore , a = (v-u)/t

=>a = (0-30)/4

=> a = -30/4 => -7.5 m/s²

force = mass × acceleration

force = 1000 kg × (-7.5) m/s²

force = -7500 kg m/s²

=> force = -7500 N

negative sign denotes opposing force

hope this helps

Answer 2

Explanation:

the distance is 60m

hope it helps you mate ........