Question

a motor car is moving with a velocity of 108km/h and it takes 4 sec to stop after the brakes are applied calculate the force exerted by the brakes on the motorcar if its mass along the passenger is 1000kg

Answer 1

Answer:

- 7500 N

Explanation:

u = 108 kmph

= 30 m/s

v = 0

t = 4 secs

therefore,

a = v-u/t

= 0-30/4 m/s^2

= -7.5m/s^2

F = m × a

= 1000 × - 7.5 N

= - 7500 N

The force is negative as brakes are applied in negative direction.