A motor car is moving with a velocity of 108km/h and it takes 4 seconds to stop after the brakes are applied. Calculate the force exerted by the breaks on the motor car. If the mass along with the passengers is 1000 kg
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initial velocity(u)= 108km/h=30m/sec
final velocity(v)=0km/h=0m/sec
mass(m)=1000kg
time(t)=4sec
force=[m(v-u)]/t
=[1000(30-0)]/4
=[1000*30]/4
=30000/4
=7500
force=7500newton
final velocity(v)=0km/h=0m/sec
mass(m)=1000kg
time(t)=4sec
force=[m(v-u)]/t
=[1000(30-0)]/4
=[1000*30]/4
=30000/4
=7500
force=7500newton
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