Question

A motor car is moving with a velocity of 108km/hr and it takes 4sec to after the brakes are applied . Calculate the force excepted by the brakes the motor if it’s mass along with the passenger is 1000kg

Answer 1

I don't know please thank me

Answer 2

Here initial velocity is 108kmph and final velocity is 0. And time =4 so convert 108kmph into m/s i. e 30m/s. Since f=m×a. So we find a=v-u/t., 0-30/4= - 7.5m/s^2.10000kg=1000×1000g.Now f=1000×1000×-7.5=-7.5×10^6kg m/s^2