A motor car is moving with velocity of 144 kmh-1 and it takes 5 sec to stop after the application of braking force . Assuming the total mass of the motorcar and passenger as 1800kg , calculate the force exerted by the brakes on the motor car
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Answer:
Explanation:
u = 108 km/h => 108×5/18 => 6×5 => 30 m/s
v = 0m/s
t = 4sec
therefore , a = (v-u)/t
=>a = (0-30)/4
=> a = -30/4 => -7.5 m/s²
force = mass × acceleration
force = 1000 kg × (-7.5) m/s²
force = -7500 kg m/s²
=> force = -7500 N
negative sign denotes opposing force
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