A motor car is travelling at 36 kmhr -1 . After 10 s, the velocity becomes 54 kmhr -1 . Assuming the
velocity change took place at uniform rate, find the acceleration.
Answers
Given:
Initial Velocity (u) of the car = 30 km/hr
Final velocity (v) of the car = 60 km/hr
Time taken (t) by the car = 10 seconds
Find:
The acceleration of the car
Solution:
We have given that,
The initial Velocity and final velocity of the car is 36 km/hr and 54 km/hr.
Convert km/hr into m/s:-
=> u = 36 × 5/18
=> u = 2 × 5
=> u = 10m/s
Convert km/hr into m/s:-
=> v = 54 × 5/18
=> v = 3 × 5
=> v = 15m/s
Acceleration = (final velocity - initial velocity)/time taken
=> A = (15 - 10)/10
=> A = 5/10
=> A = 0.5m/s².
Hence, the acceleration of the car is 0.5 m/s².
Important Information:
- Speed, Time and Distance:
- Speed = Distance/Time
- Time = Distance/speed
- Distance = Speed × Time
I hope it will help you.
Regards.
Answer:
Acceleration = (final velocity - initial velocity)/time taken
=> A = (15 - 10)/10
=> A = 5/10
=> A = 0.5m/s².
Hence, the acceleration of the car is 0.5 m/s².
Step-by-step explanation: