A motor car is travelling at m/s on a circular road ofrom radius 1200m. It is increasing its speed at the rate of 4 m/s^2. The acceleration of the car.
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Hey here is your answer-
The acceleration has 2 components : tangential (atat= 2 m/s22) and centripetal (ar=v2r=302500=1.8ar=v2r=302500=1.8m/s22).
Net acceleration = 22+1.82−−−−−−−√22+1.82m/s22 = 2.69 m/s22.
Hope it will help you.
The acceleration has 2 components : tangential (atat= 2 m/s22) and centripetal (ar=v2r=302500=1.8ar=v2r=302500=1.8m/s22).
Net acceleration = 22+1.82−−−−−−−√22+1.82m/s22 = 2.69 m/s22.
Hope it will help you.
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