Question

A motor car is travelling with speed 30 m/s on a circular road of radius 500m. Its speed is increasing at the rate of 2m/s² . What is its acceleration?

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Answer 1

Explanation:

A= v-u/t

A=34-30/1

A= 4

Answer 2

Answer:

A motor car is traveling at the speed of 30 m/s on a circular road of radius 500m. Its speed is increasing at the rate of 2m/s². Its acceleration will be $2.690\ m/s^2$

Explanation:

Acceleration (a) of an object is the ratio of its velocity and time.

An object in a uniform circular motion has tangential acceleration and radial acceleration. the radial acceleration ($a_r$) of that object is the acceleration acting along the radius, directed towards the center which can be expressed as,

$a_r = \frac{v^{2} }{r}$      

Where v is the velocity of the object and r is the radius of the circular path.

From the question,

$r = 500\ m$

$v = 30\ m/s$

Radial acceleration of the motor car,

$a_r =\frac{30^{2} }{ 500}} = 1.8\ m/s^{2}$

Increased acceleration $a_i = 2\ m/s^{2}$

Net acceleration of the car $a=\sqrt{a_{r}^{2}+a_{i}^{2}}$

$a = \sqrt{1.8^{2}+2^{2} } = 2.690\ m/s^{2}$