Physics, asked by mohan9985700, 9 months ago

A motor car moving at a
speed of 72 km/hr can not
see to a stop in less than 3
seconds while for a truck this
time interval is 5 seconds
On a highway, the car is
behind the truck, both
moving al 72 km/hr The
truck gives a signal that it is
going to stop at emergency
At whal distance the car
should be from the truck so
that it does not bump onto
(collide with) the truck
Human response time is 0. 5 second ​

Answers

Answered by ItsCrazyDaRk02
7

Answer:

Given that;

Speed of both car and truck,

v=

72 km/h

or,

v=

20 m/s

Time taken to stop the car after applying the break,

t

c

=

3.0 s

Time taken to stop the truck after applying the break

=

t

t

=

5.0 s

Therefore,

Retardation of the car, a

c

=

3

0−20

= −

3

20

m/s

2

Retardation of the truck, a

t

=

5

0−20

= −4 m/s

2

Let at time

t=

0

, the truck signals to stop and applies the break.

At time

t=

0

, let the truck and the car be at a distance

s m from each other.

Time taken by the car to travel

s m=

t

seconds.

To avoide the bump, the velocity of the car and the truck after time t should be equal.

Thus,

Velocity of the truck after time t :

v

t

= u− at

v

t

= 20− 4t

The car will apply the break after 0.5 seconds of signal.

Thus;

Velocity of car after time t will be:

v

c

= u− a(t− 0.5)

v

c

= 20−

3

20

(t− 0.5)

Therefore,

20− 4t= 20−

3

20

(t− 0.5)

t=

4

5

sec

Thus,

Distance travelled by truck in time t

s

t

= ut+

2

1

at

2

s

t

= 20×

4

5

2

1

× 4×

(

4

5

) 2

s

t

=21.875

Distance travelled by the car in t seconds, s

s

;

Distance travelled by the car in 0.5 s + distance travelled by the car in

(t−

0.5)sec

s

s

= 20× 0.5+ 20×

(

4

5

2

1

) −

2

1

×

3

20

×

(

5

4

2

1

) 2

s

s

= 23.125

Therefore, minimum distance required for the car to be distant from the truck will be

23.125−

21.875=

1.25 m

hope it's help you

Answered by Anonymous
3

❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️

✒️Your Question :-

➡️ A motor car moving at a

speed of 72 km/hr can not

see to a stop in less than 3

seconds while for a truck this

time interval is 5 seconds

On a highway, the car is

behind the truck, both

moving al 72 km/hr The

truck gives a signal that it is

going to stop at emergency

At whal distance the car

should be from the truck so

that it does not bump onto

(collide with) the truck

Human response time is 0. 5 second

____________________________

✒️Answer :-

➡️ Here,

Retardation of truck

<br> Retardation of car

<br> Let car be at a distanc e(x) from truck and (t) be the time taken to cover this distance. <br> As car decelerates only after

, so using relation,

V_(car) = 20 - ( (20) /3) (t- 0.5)

V_(truck) = 20 -4 t

20 - 4 t = 20 - (20)/3 ( t- 0.5) or 4 t = (20)/3 (t- 0.5)

t = 5/3 (t- 0.5 ) or

<br> Distance travelled by truck in this time (t), <br>

<br> Distanc etravelled by car in time (t). <br>

<br> :.

____________________________

➡️ hope this helps you ❗️❗️

✔️✔️

❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️❇️

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