Question

A motor car moving with 36km per cent is broughtto rest in 2 seconds by applyingbrakes calculating distance

Answer 1

Answer:

Initial velocity of car=36km/h or 10m/s

Final velocity of car=0m/s

Time taken by the car to come to rest=5s

Acceleration=?

By using the first equation of motion we can find out the acceleration of the car, so:

v=u+at

0=10+5a

-10=5a

-2=a

-2m/s is the retardation (acceleration done in opposite direction) of the car.

Now, we need to find the distance travelled by the car before coming to rest. In order to find out the distance we have to use second equation of motion:

s=ut+1/2at^2

s=10×5+1/2×-2×25

s=50+(-25)

s=25m

So, the distance travelled by the car before coming to rest is 25m.

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