Question

A motor car moving with a uniform speed of 20 m/
sec. comes to stop on the application of brakes after
travelling a distance of 10 m. Its acceleration is​

Answer 1

Answer:

v=0

u=20m/s

s=10m

hence

v^2=u^2+2as

20^2=-2(10)a

a=400÷-20

a=-20m/s^2

Answer 2

Answer:

-20m/s^2

Explanation:

u=20m/s, v=0(since breaks are applied). s=10m

using third eq of motion

v^2-u^2=2as

0^2-(20)^2=2.a.10

-400=20a

a=-20m/s^2