A motor car moving with a uniform velocity of 20 metre per second comes to stop on the application of brakes after travelling a distance of 10 m its acceleration is
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u=20 m/s
v=0m/s
s=10m
v^2-u^2=2as
0-400=2*a*10
-400=20a
a=-20
Hence this is a case of retardation
v=0m/s
s=10m
v^2-u^2=2as
0-400=2*a*10
-400=20a
a=-20
Hence this is a case of retardation
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Given,
=> Initial Velocity of Car = u = 20 ms^-1
=> Final Velocity = 0 m/s
=> Distance Transversed = S = 10 m
As we know that,
=> v^2 = u^2+2aS
=> 0^2 = (20)^2 + 2 x a x 10
=> 0 = 400 + 20a
=> -400 = 20a
=> -400/20 = a
=> -20 = a
=> a = -20 m/s^2
Be Brainly
=> Initial Velocity of Car = u = 20 ms^-1
=> Final Velocity = 0 m/s
=> Distance Transversed = S = 10 m
As we know that,
=> v^2 = u^2+2aS
=> 0^2 = (20)^2 + 2 x a x 10
=> 0 = 400 + 20a
=> -400 = 20a
=> -400/20 = a
=> -20 = a
=> a = -20 m/s^2
Be Brainly
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