a motor car moving with a velocity of 54km/hr is brought to rest in 1)5sec and 2)30m. find the retardation in each case
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Answer:
- a=-3m/sec²
- a=3.75m/sec²
Explanation:
we can simply use two equation of motion to solve this type of questions.
- first, Newton's first equation of motion is.
V=U+at.
0= (54*5)/18 + a5
a= -3 m/sec²
- third equation of motion is.
2as = V² - U²
a = -U²/2s
a = - (15*15)/2*30
a = - 3.75 m/sec²
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