Question

A motor car needs an engine of 5kW to keep it moving with a constant velocity of 20m/s on a horizontal road the force of friction between car tyres and ground is

Answer 1

force of friction between tyred and ground is 250 N

A motor car needs an engine of 5kW to keep it moving with a constant velocity 20m/s on horizontal road.

so, power of engine = 5kW = 5000W

we know, power = force × velocity.

here car moves in horizontal road with constant velocity. so, frictional force must equal to applied force.

so, power = friction force × velocity

⇒ 5000 = friction force × 20

⇒friction force = 250 N

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Answer 2

$\huge\bold\purple{Answer:-}$

A motor car needs an engine of 5kW to keep it moving with a constant velocity 20m/s on horizontal road.

so, power of engine = 5kW = 5000W

we know, power = force × velocity.

here car moves in horizontal road with constant velocity. so, frictional force must equal to applied force.

so, power = friction force × velocity

⇒ 5000 = friction force × 20

⇒friction force = 250 N