a motor car of 1000kg is moving with uniform velocity of 5m/s its final velocity becomes 25m/s in 4s due to applied force calculate the force
Answers
Explanation:
Final velocity(v)= 25m/s
Initial velocity(u)= 5m/s
time(t)= 4s
acceleration(a)=?
we know that a= v-u/t
putting the values we get, a=25-5/5
=20/5
=4m/s^2
mass(m)= 1000Kg
acceleration (a)= 4m/s^2
force(f)=?
we know that f= m×a
putting the values we get, f=1000×4
=4000 Newton
Given :-
☄ Mass of the motor car, m = 1000 kg
☄ Initial velocity of the car, u = 5 m/s
☄ Final velocity of the car, v = 25 m/s
☄ Time taken, t = 4s
To find :-
Force applied by the motor car
Solution :-
using equation of motion .i.e.,
➠ v = u + at
here,
v = final velocity, u = initial velocity, a = acceleration and t = time
so,
➠ 25 = 5 + (a)(4)
➠ 25 − 5 = 4a
➠ 20 = 4a
➠ a = 20/4
➠ a = 5m/s²
now, using Newton's law of motion .i.e.,
➠ F = ma
here,
F = force applied, m = mass of the motor car and a = acceleration
so,
➠ F = (1000)(5)
➠ F = 5000N
thus, the force applied on the motor car is 5000N
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