Question

A motor car of mass 1500 kg changes its velocity from 5 m/s to 25 m/s in 4 seconds calculate the force acting on it​

Answer 1

Answer:

F= ma

v=u+at

25= 5+4a

a= 5m/s2

Explanation:

F= 1500×5

= 7500

Answer 2

$\;\;\underline{\textbf{\textsf{ Given:-}}}$

•Initial velocity , u = 5 m/s

• Final velocity , v = 25 m/s

• Time , t = 4 seconds

• Mass , m = 1500 kg

$\;\;\underline{\textbf{\textsf{ To Find: -}}}$

• Force , F

$\;\;\underline{\textbf{\textsf{ Solution :-}}}$

At first, we need to find acceleration.

$\underline{\:\textsf{ As we know that :}}$

$\\ \dashrightarrow \displaystyle \sf \: Acceleration =\dfrac{ (v - u)}{t}$

$\underline{\:\textsf{ Now, put the given values in the formula :}}$

$\dashrightarrow \displaystyle \sf \: Acceleration = \frac{25 - 5}{4}$

$\dashrightarrow \displaystyle \sf \: Acceleration = \dfrac{20}{4}$

$\dashrightarrow \underline{ \boxed{\displaystyle \sf \: Acceleration = 5 \: m/s ^{2}}}$

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Now, find the force.

$\\ \\ \dashrightarrow\displaystyle \sf \:Force = mass \times Acceleration$

$\dashrightarrow\displaystyle \sf \:Force \: = 1500 \times 5$

$\dashrightarrow \underline{ \boxed{\displaystyle \sf \:Force = 7500 \: N}} \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\;\;\underline{\textbf{\textsf{ Hence-}}}$

$\therefore \underline{\displaystyle \sf \: The \: force \: acting \: on \: it \: is \: 7500 \: N.}$

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