Question

a motor car of mass 1500 kg changes its velocity from 5 ms root -1 to 25 ms root - 1 in 4 seconds calculate the force acting on it​

Answer 1

CORRECT QUESTION :-

★ A motor car of mass 1500 kg changes its velocity from 5 m/s to 25 m/s in 4 seconds calculate the force acting on it.

GIVEN :-

• Initial velocity , u = 5 m/s.
• Final velocity , v = 25 m/s.
• Time , t = 4 seconds.
• Mass , m = 1500 kg.

TO FIND :-

• The Force , F.

SOLUTION :-

$\\ : \implies \displaystyle \sf \: Acceleration =\dfrac{ (v - u)}{t}$

$: \implies \displaystyle \sf \: Acceleration = \frac{25 - 5}{4}$

$: \implies \displaystyle \sf \: Acceleration = \dfrac{20}{4}$

$: \implies \underline{ \boxed{\displaystyle \sf \: Acceleration = 5 \: m/s ^{2}}}$

___________________

$\\ \\ \dashrightarrow\displaystyle \sf \:Force = mass \times Acceleration$

$\dashrightarrow\displaystyle \sf \:Force \: = 1500 \times 5$

$\dashrightarrow \underline{ \boxed{\displaystyle \sf \:Force = 7500 \: N}} \: \: \: \: \: \: \: \: \: \: \: \: \: \bigg \lgroup \:\displaystyle \sf Force \bigg \rgroup$

$\therefore \underline{\displaystyle \sf \: The \: force \: acting \: on \: it \: is \: 7500 \: N.}$

Answer 2

Correct Question:

a motor car of mass 1500 kg changes its velocity from 5 m/s to 25 m/s in 4 seconds calculate the force acting on it ?

Answer:

Given:

• Mass of an object, m= 1500kg
• Initial Velocity, u = 5m/s
• Final Velocity, v = 25m/s
• Time t = 4 sec

Find:

• What is the force acting on it?

Solution:

Here,

we, know that,

v = u + at (1st eq. of motion)

where,

• v = 25m/s
• u = 5m/s
• t = 4 sec

So,

v = u + at

$\rm \implies 25 = 5 + a(4)$

$\rm \implies 25 - 5 = 4a$

$\rm \implies 4a = 20$

$\rm \implies a = \frac{20}{4}$

$\rm \implies a = \frac{ \cancel{20}}{ \cancel{4}} = 5$

$\rm \implies a = 5 {m/s}^{2}$

Now,

we, know that,

F = ma

where,

• m = 1500kg
• a = 5m/s²

So,

F = ma

$\rm \implies F = 1500 \times (5)$

$\rm \implies F = 7500 \: kg{m/s}^{2}$

$\rm \implies F = 7500 N$

Hence, The Force Acting On it will be 7500N