Science, asked by mohitshirpurka5477, 11 months ago

A motor car starting from rest moves with uniform acceleration and attains a velocity of 8 ms ‘ in 8 s. It then moves with uniform velocity and is finally brought to rest in 32 m under uniform retardation. The total distance covered by the car is 464 m. Find the value of acceleration, retardation and the total time is taken.

Answers

Answered by deleteaccount81
8

V=Vo+ at

8=0+a(8)

a=1 m/s².........(i)

retardation = (-1) m/s².......(ii)

8 seconds for acceleration and 8 seconds for retardation and time t for uniform velocity.

t = 400/32=12.5 seconds

total time taken = 8+8+12.5=16+12.5

=28.5 seconds.......(iii)

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