A motor car starting from rest moves with uniform acceleration and attains a velocity of 8 ms ‘ in 8 s. It then moves with uniform velocity and is finally brought to rest in 32 m under uniform retardation. The total distance covered by the car is 464 m. Find the value of acceleration, retardation and the total time is taken.
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V=Vo+ at
8=0+a(8)
a=1 m/s².........(i)
retardation = (-1) m/s².......(ii)
8 seconds for acceleration and 8 seconds for retardation and time t for uniform velocity.
t = 400/32=12.5 seconds
total time taken = 8+8+12.5=16+12.5
=28.5 seconds.......(iii)
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