Question

A motor car takes 10 seconds to cover 30 meters and 12 seconds to cover 42 meters. Find theuniform acceleration ​

Answer 1

Answer:

0.25m/s²

Explanation:

initial velocity =30/10=3m/s

final =42/12=3.5m/s

acceleration =0.5 m/s²

time=12-10 (from where acceleration starts)

=2s

uniform acceleration =0.5/2=0.25m/s²

Answer 2

Answer:

Case I

Distance covered by car =30 metres

Time taken = 10 second

So as velocity =distance /time

velocity =30/10 = 3m/sec

Case II

Distance travelled =42 metres

Time taken =12 seconds

Then, velocity =distance /time

velocity =42 /12 =7/2=3.5 m/sec

Also, change in time =(12-10)seconds =2 seconds

Now as, Acceleration =[change in velocity /change in time]

Acceleration =(3.5-3)/2 ms¯²

Acceleration =0.5/2 ms¯²

Acceleration =0.25 ms¯².

Now, by using the first equation of motion,

v=u+at

Note :Velocity after 15th second =velocity before 16 seconds.

Then,

v = 0 +( 0.25)×(16)

v = 4 m/s.

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