Question

a motor car travelled 100 km at a velocity of 40 km/hr and came back with a velocity of 25 km/hr. Find the average speed.​

Answer 1

${\huge{\boxed{\mathcal{\red{Answer}}}}}$

19km/h

${\huge{\boxed{\mathcal{\red{Explanation}}}}}$

The average speed of a body is the ratio of total distance travelled to total time taken.

It is given un first case :

Car travels distance = 100m

speed = 40km/h

And it return with

distance travelled = 100m

speed = 25km/h

Now in the first case let the time taken be

$t_1$

So in first case time :

$t_1 = \frac{100}{40} = dis \div speed$

$t_1 = \frac{100}{40}$

$t_1 = \frac{5}{2} sec$

$t_1 = 6.5sec$

And the time that car takes to return back is

$t_2 = dis \div speed$

$t_2 = \frac{100}{25}$

$t_2 = 4sec$

Now the average speed :

$\frac{100 + 100}{t_1 +t_2 \: \: }$

$\frac{200}{4 + 6.5}$

$= \frac{200}{10.5}$

$= 19$

Thus the average speed of car is 19km/h.

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BY SCIVIBHANSHU

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Answer 2

Answer:

sorry Mujhe pata nahi h eska answer chahiye