Question

a motor car travels at a speed of 36 km/h. After 10 seconds, the velocity becomes 54/h. Assuming the velocity change took place at an uniform rate, Find the acceleration.

Answer 1

solution

initial velocity, u= 36km/h

final velocity, v= 54km/h

time taken, t= 10 sec= 1/6min= 1/360 hour

now, a= v-u/t

=> a= 54-36/360

= 18/360

=0.5 m/s^2

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Answer 2

$Hi \: there \: \\ \\ Initial \: \: Velocity \: , u \: = \: 36 km /h \\ \\ final velocity , v = 54 km /h \\ \\ Time \: taken \: in \: change \: in \: velocity \: , t = 10 /3600 \\ now \\ \\ acceleration \: = \frac{v - u}{t} \\ \\ = \frac{54 - 36}{360} \\ \\ = \frac{18}{360} \: \: \: km {h}^{ - 2} \\ \\ = 0.05 \: \: \: km {h}^{ - 2} \:$

In terms of m {s}^{-2}

it will be = 0.5 m {s}^{-2}

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