Question

A motor cycle has initial velocity 6m/s accelerate for 10 sec at the rate 0.50 meter per second square. Its final velocity will be ? (Alevel)​

Answer 1

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${\bigstar \:{\pmb{\sf{\underline{Provided \: that...}}}}}$

⠀⠀⠀⠀⠀⠀A motor cycle has initial velocity 6 m/s accelerated for 10 seconds at the rate 0.50 meter per second sq. Then it's final velocity will be?

$\sf According \: to \: statement \begin{cases} & \sf{Initial \: velocity \: = \bf{6 \: m/s}} \\ \\ & \sf{Time \: taken \: for \: accelerated \: = \bf{10 \: seconds}} \\ \\ & \sf{Acceleration \: = \bf{0.50 \: m/s^{2}}} \\ \\ & \sf{Final \: velocity \: = \bf{?}} \end{cases}$

${\bigstar \:{\pmb{\sf{\underline{Solution...}}}}}$

⋆ As a motor cycle has initial velocity 6m/s accelerate for 10 seconds at the rate 0.50 meter per second square. Its final velocity will be 11 m/s

${\bigstar \:{\pmb{\sf{\underline{Using \: concept...}}}}}$

⋆ First law of equation of motion

${\bigstar \:{\pmb{\sf{\underline{Using \: formula...}}}}}$

⋆ First law of equation of motion is given by the mentioned formula:

⠀⠀⠀⠀⠀${\underline{\boxed{\sf{\longrightarrow v \: = u + at}}}}$

(Where, v denotes final velocity , u denotes initial velocity , a denotes acceleration and t denotes time)

${\bigstar \:{\pmb{\sf{\underline{Full \: Solution...}}}}}$

$:\implies \sf v \: = u + at \\ \\ :\implies \sf v \: = 6 + 0.50(10) \\ \\ :\implies \sf v \: = 6 + 05.00 \\ \\ :\implies \sf v \: = 6 + 5 \\ \\ :\implies \sf v \: = 11 \\ \\ :\implies \sf Final \: velocity \: = 11 \: m/s$

Answer 2

Answer:

⟹v=u+at

⟹v=6+0.50(10)

⟹v=6+05.00

⟹v=6+5

⟹v=11

⟹Finalvelocity=11m/s

Therefore it's final velocity will be 11m/s

Explanation:

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