Question

A motor cycle is being driven at a speed of 20 m/s when brakes are applied to bring it to rest in five seconds the deccerlation produced in case is?​

Answer 1

Answer:

In this case,

u (Initial Velocity) = 20 m/sec

v (final velocity) = 0 m/sec (at rest)

time (t) = 5 secs

a = (v-u) /t

a= (0 - 20) / 5

a= -20 / 5

a = -4 m/sec square

Therefore Deceleration produced is 4 m/sec square

Explanation:

I hope it's helpful.

Answer 2

AnswEr :

Given that a motor cycle is being driven at a speed of 20 m/s. When brakes are applied it comes to rest in 5 seconds.

We have to find deceleration produced in the case.

From the given conditions we have :

➡ Initial speed (u) = 20 m/s

➡ Final speed (v) = 0 m/s [∵ It comes to rest]

➡ Time (t) = 5 seconds.

As we know the 1st equation of motion, we will use that equation here :-

→ v = u + at

Substituting values,

→ 0 = 20 + a × 5

→ 0 = 20 + 5a

→ 5a + 20 = 0

→ 5a = -20

→ a = -20/5

→ a = -4 m/s²

[∵ Acceleration = - Deceleration ]

∴ Deceleration (d) = 4 m/s²

∴ Deceleration produced in that case = 4 m/s² or, acceleration is -4 m/s² [Answer]